Please show steps to solve the following: lnx^9 = (lnx)^2 + 20 any help would be appreciated. thanks
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Originally Posted by sandra17 Please show steps to solve the following: lnx^9 = (lnx)^2 + 20 any help would be appreciated. thanks ln x^9 = (ln x)^2 +20 9*ln x = (ln x)^2 +20 (ln x)^2 - 9*ln(x) + 20 =0 y^2 - 9y+20 =0 where y=ln x. Solve this quadradic yourself.
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