Please show steps to solve the following:
lnx^9 = (lnx)^2 + 20
any help would be appreciated.
thanks
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Please show steps to solve the following:
lnx^9 = (lnx)^2 + 20
any help would be appreciated.
thanks
ln x^9 = (ln x)^2 +20Quote:
Originally Posted by sandra17
9*ln x = (ln x)^2 +20
(ln x)^2 - 9*ln(x) + 20 =0
y^2 - 9y+20 =0 where y=ln x.
Solve this quadradic yourself.