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Math Help - Dividing a quadratic by a linear.

  1. #1
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    Dividing a quadratic by a linear.

    i am lost with problems like these, can someone please help and explain step by step?
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    Last edited by mr fantastic; February 25th 2010 at 01:20 AM. Reason: Changed post title
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  2. #2
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    Factorise both the numerator and denominator.

    Numerator:

    2x^2-x-3

    That can be factorised to: (x+1)(2x-3)

    Denominator:

    x-1

    That can be factorised to: (x+1)(x-1)

    Now we have a fraction that looks like this:

    \frac{(x+1)(2x-3)}{(x+1)(x-1)}

    Now have a think of what you do next....
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  3. #3
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    Quote Originally Posted by jgv115 View Post
    Factorise both the numerator and denominator.

    Numerator:

    2x^2-x-3

    That can be factorised to: (x+1)(2x-3)

    Denominator:

    x-1

    That can be factorised to: (x+1)(x-1)
    No, it can't! You were thinking of x^2- 1.

    Now we have a fraction that looks like this:

    \frac{(x+1)(2x-3)}{(x+1)(x-1)}

    Now have a think of what you do next....
    That should be \frac{(x+1)(2x-3)}{x-1}

    By the way, wonderd, you never did say what you wanted to do with that expression!
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  4. #4
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    Quote Originally Posted by wonderd View Post
    i am lost with problems like these, can someone please help and explain step by step?
    You're probably expected to do a polynomial long division to get the result here: simplify (2x^2 - x - 3)/(x - 1) - Wolfram|Alpha

    Your textbook and class notes should have examples ....?
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    Oops Thanks for clearing that up hallsofivy =="
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