1. ## Dividing a quadratic by a linear.

2. Factorise both the numerator and denominator.

Numerator:

$\displaystyle 2x^2-x-3$

That can be factorised to: $\displaystyle (x+1)(2x-3)$

Denominator:

$\displaystyle x-1$

That can be factorised to: $\displaystyle (x+1)(x-1)$

Now we have a fraction that looks like this:

$\displaystyle \frac{(x+1)(2x-3)}{(x+1)(x-1)}$

Now have a think of what you do next....

3. Originally Posted by jgv115
Factorise both the numerator and denominator.

Numerator:

$\displaystyle 2x^2-x-3$

That can be factorised to: $\displaystyle (x+1)(2x-3)$

Denominator:

$\displaystyle x-1$

That can be factorised to: $\displaystyle (x+1)(x-1)$
No, it can't! You were thinking of $\displaystyle x^2- 1$.

Now we have a fraction that looks like this:

$\displaystyle \frac{(x+1)(2x-3)}{(x+1)(x-1)}$

Now have a think of what you do next....
That should be $\displaystyle \frac{(x+1)(2x-3)}{x-1}$

By the way, wonderd, you never did say what you wanted to do with that expression!

4. Originally Posted by wonderd