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Math Help - Wow... I am stumped!

  1. #1
    Newbie
    Joined
    Mar 2007
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    2

    Wow... I am stumped!

    [(4x+6 / 3x-1) + 6 ] / [(12x+18 / 9x-3) -4]

    I tried to format it the best way I could... on my paper, it looks more like:

    4x+6
    ----- +6
    3x-1
    12x+18
    ------- -4
    9x-3

    I can't figure this out for the life of me..

    I am trying to prove that these are inverse. So I want the whole thing to equal x.
    I don't know what this process is called.. but I just know I have to do the
    f(x) of f^-1(x)
    then
    f^-1(x) of f(x)
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  2. #2
    Super Member
    earboth's Avatar
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    Jan 2006
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    Germany
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    Quote Originally Posted by sanders4617 View Post
    [(4x+6 / 3x-1) + 6 ] / [(12x+18 / 9x-3) -4]

    I tried to format it the best way I could... on my paper, it looks more like:

    4x+6
    ----- +6
    3x-1
    12x+18
    ------- -4
    9x-3

    I can't figure this out for the life of me..

    I am trying to prove that these are inverse. So I want the whole thing to equal x.
    I don't know what this process is called.. but I just know I have to do the
    f(x) of f^-1(x)
    then
    f^-1(x) of f(x)
    Hello,

    honestly I don't understand completely what you want tot do...

    But I can show you how to simplify this term. See attachment.

    Maybe this can help you a little bit further.

    EB
    Attached Thumbnails Attached Thumbnails Wow... I am stumped!-bruchterm.gif  
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  3. #3
    Newbie
    Joined
    Mar 2007
    Posts
    2
    Well I took a test on this section today... I believe I made a 100.. there was one problem where I wasn't sure though, so I just hope I got it right.

    The problem that I listed wasn't on the test.. the kind of problem was, but it was a much shorter version.

    It was basically doing the f of f-1 and f-1 of f stuff.. Don't know the proper name though.
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