Hi,

I need to solve two quadratics simultaneously to find the x and y values,

they are:

x^2 + y^2 = 0.23

(x-0.15)^2 + (y-0.175)^2 = 0.16

Thank you

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- February 23rd 2010, 12:07 PMsweetiepieSimultaneous quadratic equations
Hi,

I need to solve two quadratics simultaneously to find the x and y values,

they are:

x^2 + y^2 = 0.23

(x-0.15)^2 + (y-0.175)^2 = 0.16

Thank you - February 23rd 2010, 12:15 PMicemanfan
Start with the second equation and expand it out:

Now substitute in for :

Now solve for y in terms of x and substitute y = f(x) back into the first equation:

Now you have a quadratic equation in terms of x which can be solved using the quadratic formula. - February 23rd 2010, 12:55 PMsweetiepie
Thanks for helping me but when I substitute in the results I get from the quadratic formula into the two equations I do not get the correct result,

Can someone show me how to get to the quadratic formula so I can check my answers please? - February 23rd 2010, 05:37 PMHallsofIvy
That should work. How about if YOU show your work and why you think the answer you got was wrong?

- February 24th 2010, 06:15 AMsweetiepie
**Forming an equation in y:**

0.35y = 0.123125 - 0.3x

y =(0.123125 - 0.3x)/0.35

**Substitute into x^2 + y^2 = 0.23 gives:**

x^2 + ((0.123125 - 0.3x)/0.35)^2 = 0.23

**Expanding brackets:**

x^2 + (0.09x^2 - 0.6x + 0.015159765)/(0.35^2) = 0.23

**Multiplying both sides by (0.35^2):**

0.1225x^2 + 0.09x^2 - 0.6x + 0.015159765 = 0.028175

**Forming quadratic equation:**

0.2125x^2 - 0.6x - 0.013015235 = 0

**Solving with quadratic formula:**

a = 0.2125

b = -0.6

c = -0.013015235

b^2 = 0.36

4ac = -0.011062949

b^2 - 4ac = 0.371062949

sqrt(b^2 - 4ac) = 0.609149365

-b - ans = -0.009149365

-b + ans = 1.209149366

x = 2.845057332

or

x = -0.021527917

**Substituting back into first equation:**

when x = 2.845057332, y = NaN

when x = -0.021527917, y = 0.4790997272900794

**Checking in equation 2:**

(-0.021527917 - 0.15)^2 + (0.4790997272900794 - 0.175)^2 = 0.12189847124672402

*The answer doesnt equal 0.16, can someone please explain what I have done wrong?*