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    factorising this

    6(x-3)^2+13(x-3)+5
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  2. #2
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    Quote Originally Posted by johnsy123 View Post
    6(x-3)^2+13(x-3)+5
    Use a dummy variable X = x - 3 so that the expression becomes

    6X^2 + 13X + 5

     = 6X^2 + 3X + 10X + 5

     = 3X(2X + 1) + 5(2X + 1)

     = (2X + 1)(3X + 5)

    And since X = x - 3, this becomes

    [2(x - 3) + 1][3(x - 3) + 5]

     = (2x - 6 + 1)(3x - 9 + 5)

     = (2x - 5)(3x - 4).
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