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Math Help - Help me, please! Simple log solve for X

  1. #1
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    Help me, please! Simple log solve for X

    Hi. I'm a n00b and need to refresh my memory. I've not done this in a very long time.

    How do I solve for X?

    30 = 10lg(20/x)

    Please, show me the basic steps. Thank you.
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  2. #2
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    Quote Originally Posted by mathsgre View Post
    Hi. I'm a n00b and need to refresh my memory. I've not done this in a very long time.

    How do I solve for X?

    30 = 10lg(20/x)

    Please, show me the basic steps. Thank you.
    The "inverse" of a logarithem is an exponential. Start, of course, by dividing both sides by 10: 3= lg(20/x). Assuming the your "lg" means natural logarithm, take exp of or "e" to the power of both sides. e^3= \frac{20}{x}. Can you solve it now?
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  3. #3
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    Yes. I remember now. Thank you very much.
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