Printable View

(1 + x + x^2)/(1 – x + x^2) = [62(1 + x)]/[63(1 – x)]

Hello snigdha Quote: Originally Posted by snigdha (1 + x + x^2)/(1 – x + x^2) = [62(1 + x)]/[63(1 – x)] Re-write the equation as: $\displaystyle 63(1-x)(1+x+x^2)=62(1+x)(1-x+x^2)$Remove brackets and simplify, to: $\displaystyle 125x^3=1$ $\displaystyle \Rightarrow x = \tfrac15$ Grandad