i have started this , but unable to find a way to complete it, any hints?

Q: in order to test a model of the form y=ab^x, a student plots a graph of log y against x for her values of x and y. The points lie in a straight line, with the gradient 0.65. the straight line meets the log y axis at the point (0,1.05)

a) find the values of a and b correct to 1.d.p

b) hence find the value of y, given by the model, wehn x=3

Workings so far

y=ab^x

logy=logab^x

logy=loga + xlogb

logy=xlogb +loga => which in relation is y=mx+c

i know that loga=1.05 which is where it crosses the y axis

and that xlogb=0.65 which is the gradient

but here is where i get stuck. i'm not sure how to reverse log or something like that to work out a and b