$\displaystyle 4 (5^ {-3x+2}) = 100 $ Please help, I have no idea how to solve this. I have some basis of exponent rules, but what do I do? Do I have to factor?
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Originally Posted by needhelpplease1 $\displaystyle 4 (5^ {-3x+2}) = 100 $ Please help, I have no idea how to solve this. I have some basis of exponent rules, but what do I do? Do I have to factor? $\displaystyle 4 (5^{-3x+2}) = 100 $ divide both sides by 4 ... $\displaystyle 5^{-3x+2} = 25$ $\displaystyle 5^{-3x+2} = 5^2$ finish it.
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