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Math Help - Rates Word Problem

  1. #1
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    Rates Word Problem

    Ray and Jane live 150 miles apart, each drives toward the other's house along a straight road connecting the two. Ray at a constant 30 mph, and Jane at a constant 50 mph. If Ray and Jane leave their houses at the same time, how many miles are they from Ray's house when they meet?

    I know the answer, I just need an explanation.

    The way the book explained it was that by adding up the rates and dividing that in 150, and then multiplying that by Ray's rate. But I don't understand WHY you should add up the rates.

    If you can explain that, or give a more lucid explanation that would be perfect.

    On another note, does anyone know any websites with good Rates practice problems like this one?
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  2. #2
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    Quote Originally Posted by Alan306090 View Post
    Ray and Jane live 150 miles apart, each drives toward the other's house along a straight road connecting the two. Ray at a constant 30 mph, and Jane at a constant 50 mph. If Ray and Jane leave their houses at the same time, how many miles are they from Ray's house when they meet?

    I know the answer, I just need an explanation.

    The way the book explained it was that by adding up the rates and dividing that in 150, and then multiplying that by Ray's rate. But I don't understand WHY you should add up the rates.

    If you can explain that, or give a more lucid explanation that would be perfect.

    On another note, does anyone know any websites with good Rates practice problems like this one?
    together, they travel a combined 150 miles when they meet.

    30t + 50t = 150 , where t is the time in hrs when they meet.

    solve the equation for t, then calculate the value of 30t to ATQ.
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