# Thread: Rates Word Problem

1. ## Rates Word Problem

Ray and Jane live 150 miles apart, each drives toward the other's house along a straight road connecting the two. Ray at a constant 30 mph, and Jane at a constant 50 mph. If Ray and Jane leave their houses at the same time, how many miles are they from Ray's house when they meet?

I know the answer, I just need an explanation.

The way the book explained it was that by adding up the rates and dividing that in 150, and then multiplying that by Ray's rate. But I don't understand WHY you should add up the rates.

If you can explain that, or give a more lucid explanation that would be perfect.

On another note, does anyone know any websites with good Rates practice problems like this one?

2. Originally Posted by Alan306090
Ray and Jane live 150 miles apart, each drives toward the other's house along a straight road connecting the two. Ray at a constant 30 mph, and Jane at a constant 50 mph. If Ray and Jane leave their houses at the same time, how many miles are they from Ray's house when they meet?

I know the answer, I just need an explanation.

The way the book explained it was that by adding up the rates and dividing that in 150, and then multiplying that by Ray's rate. But I don't understand WHY you should add up the rates.

If you can explain that, or give a more lucid explanation that would be perfect.

On another note, does anyone know any websites with good Rates practice problems like this one?
together, they travel a combined 150 miles when they meet.

30t + 50t = 150 , where t is the time in hrs when they meet.

solve the equation for t, then calculate the value of 30t to ATQ.