Okay I'm not even sure if this even is a simultaneous equation, but I don't know how to solve it anyway..
x+y=60
x^2 = 0.25
y^2
Find x and y.
It's part of a massive a level physics question and I've simplified it a lot, so no I'm not a 12 year old asking for the answers to his maths homework :P
Changing the second around a bit, you get the much simpler
4x^2 = y^2
It is now your responsibility to remember that y = 0 is inappropriate.
If we KNOW that x and y are greater than zero (0), we get:
2x = y
Do we KNOW that x and y are greater than zero (0)?
Simultaneous solution is rather simple after that.
Yes x and y are greater than zero
Okay thanks a lot, that did it and got the correct answer. But out of interest, how did you go from 4x^2 = y^2 to 2x = y? Is that just a general rule when x and y are greater than 0?
Hi Magma828,Originally Posted by Magma828
Yes x and y are greater than zero
Okay thanks a lot, that did it and got the correct answer. But out of interest, how did you go from 4x^2 = y^2 to 2x = y? Is that just a general rule when x and y are greater than 0?
TK took the square root of each side of the equation.
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