for the circle x^2+y^2+2gx+2fy+c=0-----(1) the equation of the tangent at the point (x1,y1) is xx1+yy1+2g(x+x1)+2f(y+y1)+c=0(this is given in textbooks if you ask me how).comparing the given equations with this equation you will get the 2 points (x1,y1)=(1,-3) and (x2,y2)=(3,-1). so u have 3 points and 3 equations in f,g,c by putting the points in (1). you should get the answers therefore.