Word problem regarding simulateous equations again.

• Feb 17th 2010, 04:50 PM
Word problem regarding simulateous equations again.
2 questions here.
1 number is 9 times another number. The sum of the numbers is 260. What is the smaller number.
If you are to use X &Y I am lost here. Or do you???

Also.
The perimeter of a rectangle lot is 200 meters. The length is 25 meters more than 2 times the width. Find the length of the lot.

Lost on this one also,
Fully explain so I can understand it, thanks.
Jo
• Feb 17th 2010, 05:04 PM
pickslides
Quote:

2 questions here.
1 number is 9 times another number. The sum of the numbers is 260. What is the smaller number.
If you are to use X &Y I am lost here. Or do you???

\$\displaystyle x\$ is one number, the other is \$\displaystyle 9x\$ as it is 9 times bigger.

Now \$\displaystyle 9x + x = 260\$

Can you finish it?
• Feb 17th 2010, 05:07 PM
pickslides
Quote:

The perimeter of a rectangle lot is 200 meters. The length is 25 meters more than 2 times the width. Find the length of the lot.

lets say width is \$\displaystyle x \$ therefore length is \$\displaystyle x + 25\$

\$\displaystyle P = 2(l+w)\$

From what we know \$\displaystyle 200 = 2(x+(x+25))\$

Expand and solve.
• Feb 17th 2010, 05:34 PM
Diagonal
Quote:

Originally Posted by pickslides
lets say width is \$\displaystyle x \$ therefore length is \$\displaystyle x + 25\$

If 25 more than 2 times the width, isn't that 2x + 25 ?
• Feb 17th 2010, 05:45 PM
pickslides
Quote:

Originally Posted by Diagonal
If 25 more than 2 times the width, isn't that 2x + 25 ?

Yep, must have read over that a little quick.