Function = (X+2)\(X+1)
When X = -1 for a function, it says "ERROR" on the calculator.
So if this is an asymtote, doesn't that mean the range would be all real numbers as the values between -2 and -1 would reach infinity?
Can someone explain why this reasoning is wrong? The real answer is supposed to be all real numbers except 1.
Yes, your reasoning is correct, since there is a vertical asymptote, there will be no upper- or lower limit to the range. However, you need to check for horizontal asymptotes.
This means that is a horizontal asymptote and can't be part of the range.
Do you understand?
Hope I helped you