Cancel out 2 then square:
23 is prime and so solve using quadratic formula
However, if we put these solutions back into the original equation we find that - it is an extraneous root so it should be discarded
does equal 0 when put into the original equation so this is a root
The numerator must be zero, so ignore the denominator, except to see limitations of acceptable values [x NOT<=-2 or it is undefined or complex.]
Divide by 2 to simplify.
Move the radical to one side [watch for sign change] and square both sides.
Give it a try.