X^4 - 2x - 8 = 0

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- March 24th 2007, 01:14 PM #1

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- March 24th 2007, 01:36 PM #2
that's a hard one. it has no rational roots. and thinking up irrational roots is, well, pretty impossible. you probably have to use the "general formula" for solving quartic equations, which i can tell you is really complicated. check to see if you have a typo before looking it up

- March 24th 2007, 01:39 PM #3

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- March 24th 2007, 01:48 PM #4
so yeah, like i said, there's no nice way to solve this. there are no rational roots. the roots are irrational, so you can't really come up with any (unless you're a super super genius). try looking up the general formula. did your professor mention that you would need it?

- March 24th 2007, 03:00 PM #5
let me follow up that question with this: Where did you get this question? Was it in a book? On a test? In a handout? Something your teacher wrote up on the board?

I can tell you with relative certainty this problem cannot be solved. To be specific, it CAN be solved if you plug it into a formula that is at least 10 pages long. Don't worry about finding the roots to this.

- March 24th 2007, 03:02 PM #6
yeah, i actually tried doing this, (not completely by hand, i used a site to compute some parts), and i was getting complex numbers in intermediate steps, so i couldn't complete it. when i used a graphing utility to graph it, it showed two real roots, but i don't see how to get to them

- March 24th 2007, 08:28 PM #7

- March 24th 2007, 08:31 PM #8

- March 25th 2007, 05:03 AM #9
I can understand your confusion over this polynomial equation but you were told (by me) in another post that this has to be done numerically. If you have a question about something I told you I'd appreciate it if you would ask in the same thread so that it's on topic.

The fact that this is the second time you posted this question AFTER I gave you a solution strikes me as being rather rude.

-Dan

- March 25th 2007, 12:41 PM #10

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sry topsquark... didnt think you would take it soo.....personal.. but anyway ya its a problem on a test.. i was absent for the test and he let me take it home ummm idk i guess monday ill go up to him and ask him after he grades it can he explain what he wanted for the problem because he didnt tell me anything special about it... "solve each polynomial equation" thats all the test says