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Math Help - Problem solving with quadratics

  1. #1
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    Exclamation Problem solving with quadratics

    question 1: A rectangular box has a square base and its height is 1 cm longer than the length of one side of its base.
    the total surface area is given by
    A= 6X^2+ 4X

    If the total surface area is 240 cm^2, find the dimensions of the box.





    Question 2: An open box contains 80 cm^3 and is made from a square piece of tinplate with 3 cm squares cut from each of its 4 corners. Find the dimensions of the original piece of tinplate.




    Question 3: Is it possible to bend a 20 cm length of wire into the shape of a rectangle which has an area of 30 cm^2?
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  2. #2
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    Quote Originally Posted by Tessarina View Post
    question 1: A rectangular box has a square base and its height is 1 cm longer than the length of one side of its base.
    the total surface area is given by
    A= 6X^2+ 4X

    If the total surface area is 240 cm^2, find the dimensions of the box.

    Lets say the width and length of the square base is x and the height is x+1

    From the information given,

     240 = 6x^2+ 4x

     0 = 6x^2+ 4x- 240

     0 = 3x^2+ 2x- 120

    Now find x using the quadratic formula, disgard any negative values.
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