(2X^2 - 7X - 15)/(2X^3 + 13X^2 + 15X) If X is greater than 10, then why is (x-5)\(x^2 + 5x) equivalent to it? And why can't X = -3\2?
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Originally Posted by Alan306090 (2X^2 - 7X - 15)/(2X^3 + 13X^2 + 15X) If X is greater than 10, then why is (x-5)\(x^2 + 5x) equivalent to it? And why can't X = -3\2? Can you see here that you can't let ? If you did the denominator would be . Now cancelling gives .
Originally Posted by Alan306090 (2X^2 - 7X - 15)/(2X^3 + 13X^2 + 15X) If X is greater than 10, then why is (x-5)\(x^2 + 5x) equivalent to it? And why can't X = -3\2? This has no value if x=0, x= -5 and 2x = -3. You can cancel the term (2x+3) only if (2x+3) is not zero. Since in that case you have 0/0. However, if x>0, you can cancel those terms and then we can say it's the same as
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