Solving for H(g(f(x)))
Hi, i've been posed a maths tutorial on functions and i'm just looking for someone to check my answer. I would get a classmate or lecturer to do it, but it's reading week and no-one is around.
So, With that in mind.
Given f(x)= 4x + 6 , g(x)= 2xSquared -3x + 5, and h(x)= 6x, find h(g(f(x)))
here's my answer
g(f(x))= 2(4x-6)squared -3(4x-6) + 5
-> 2(16x -36) -3(4x-6) + 5
-> (32x - 72) (12x-18) + 5
-> (44x - 90 + 5)
h(g(f(x))) = 6(44x - 90 + 5)
->(264x 540 + 30)
h(g(f(x)))= 264x -540 + 30
Did i mess up along the way or does this look right?
Any pointers you can give me would be good, as well as a way to display the character for squared, cubed etc. thanks in advance. Also apologies if i got this in the wrong forum.
You're method looks good to me but you've been a little careless when multiplying out the brackets, note that:
Hope this helps
ok, thank you, ill go back and redo.
could you go into a little more detail explaining the steps done?
Originally Posted by NeilT
such as how you got the ? thanks.
Ok so, for simplicity lets ignore the 2 at the start as we can just double at the end to get our answer. When we multiply two brackets together we use the "distributive law" for multiplcation whch basically says take each element of the frst bracket and multiply it by every term in the next bracket eg:
Originally Posted by Sarcasticus
or as in this case
Hope that clears it up for you
Thanks. I think i get the whole becoming . , most teachers dont explain that particular bit has 2 mini parts.
Thanks again, you've saved my bacon.