a^2-b^2 - 2ac+2bc My answer: 1(a-b)(a+b) -2c(a-b) Thanks guys. Best regards.
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Originally Posted by Samurai111 a^2-b^2 - 2ac+2bc My answer: 1(a-b)(a+b) -2c(a-b) Thanks guys. Best regards. There's a common factor of $\displaystyle a - b$. So $\displaystyle (a - b)(a + b) - 2c(a - b) = (a - b)(a + b - 2c)$...
Hi man, and thanks a lot for the fast response! Knew I was missing something. Cheers!
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