How would one solve for x in the following, using the laws of logarithms?

1) 5^x+3^2x=92

2) 4*5^x-3*0.4^2x=11

In 1), this is what I've done so far:

5^x+3^2x=92

log(5^x+3^2x)=log 92

log(5+3^2)^x=log 92

x log 14=log 92

but I don't think that it's correct, and things aren't any clearer for question 2).