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Math Help - soving exponential equations #2

  1. #1
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    Unhappy soving exponential equations #2

    In my previous post, I wrote the question incorrectly. Please help!!

     2^ {x^2} \;=\;32(2^{4x})
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  2. #2
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    Quote Originally Posted by needhelpplease1 View Post
    In my previous post, I wrote the question incorrectly. Please help!!

     2^ {x^2} \;=\;32(2^{4x})
     2^ {x^2} \;=\;32(2^{4x})\Leftrightarrow 2^{x^2}=2^{5+4x}\implies x^2=5+4x
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  3. #3
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    Unhappy but...

    Quote Originally Posted by felper View Post
     2^ {x^2} \;=\;32(2^{4x})\Leftrightarrow 2^{x^2}=2^{5+4x}\implies x^2=5+4x
    thanks, but how do you solve for x?
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  4. #4
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    Quote Originally Posted by needhelpplease1 View Post
    thanks, but how do you solve for x?
    The solution that you obtain in that equation, is the same of your original equation!
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