# Math Help - soving exponential equations #2

1. ## soving exponential equations #2

In my previous post, I wrote the question incorrectly. Please help!!

$2^ {x^2} \;=\;32(2^{4x})$

2. Originally Posted by needhelpplease1
In my previous post, I wrote the question incorrectly. Please help!!

$2^ {x^2} \;=\;32(2^{4x})$
$2^ {x^2} \;=\;32(2^{4x})\Leftrightarrow 2^{x^2}=2^{5+4x}\implies x^2=5+4x$

3. ## but...

Originally Posted by felper
$2^ {x^2} \;=\;32(2^{4x})\Leftrightarrow 2^{x^2}=2^{5+4x}\implies x^2=5+4x$
thanks, but how do you solve for x?

4. Originally Posted by needhelpplease1
thanks, but how do you solve for x?
The solution that you obtain in that equation, is the same of your original equation!