# Thread: soving exponential equations #2

1. ## soving exponential equations #2

$2^ {x^2} \;=\;32(2^{4x})$

$2^ {x^2} \;=\;32(2^{4x})$
$2^ {x^2} \;=\;32(2^{4x})\Leftrightarrow 2^{x^2}=2^{5+4x}\implies x^2=5+4x$

3. ## but...

Originally Posted by felper
$2^ {x^2} \;=\;32(2^{4x})\Leftrightarrow 2^{x^2}=2^{5+4x}\implies x^2=5+4x$
thanks, but how do you solve for x?

thanks, but how do you solve for x?
The solution that you obtain in that equation, is the same of your original equation!