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Math Help - Solving matrix equations

  1. #1
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    Solving matrix equations

    P is a 2 times 2 matrix.Determine p if
    Attached Thumbnails Attached Thumbnails Solving matrix equations-matrix.jpg  
    Last edited by mastermin346; February 10th 2010 at 01:27 AM. Reason: wrong write
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  2. #2
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    Have you even tried to do this yourself? It's very straight forward.

    3\begin{bmatrix}1 & 0 \\ 2 & 4\end{bmatrix}- 2P= \begin{bmatrix}-2 & -3 \\ 4 & -5\end{bmatrix].

    Since P must be a 2x2 matrix in order to be able to subtract 2P, write it as [tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix}:

    3\begin{bmatrix}1 & 0 \\ 2 & 4\end{bmatrix}- 2\begin{bmatrix}a & b \\ c & d\end= \begin{bmatrix}-2 & -3 \\ 4 & -5\end{bmatrix].

    Do the indicated calculations and you will have 4 separate linear equations for a, b, c, and d. For example, one equation is 1- 2a= -2. That's easy to solve.
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  3. #3
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    Quote Originally Posted by mastermin346 View Post
    P is a 2 times 2 matrix.Determine p if
    let  \begin{bmatrix}<br />
1 & 0\\ <br />
2 & 4<br />
\end{bmatrix} be A

    and let
    \begin{bmatrix}<br />
-2 & -3\\ <br />
4 & -5<br />
\end{bmatrix} be C.

    So we have 3A-2P=C

    to find P, rearange it

    -P=\frac{C-3A}{2}

    P=-\frac{C-3A}{2}

    Can you do it now?
    Last edited by BabyMilo; February 10th 2010 at 10:50 AM.
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