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Math Help - indice thing 1

  1. #1
    Senior Member furor celtica's Avatar
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    indice thing 1

    (2^100) - (2^99)
    im supposed to be doing pretty advance stuff but this just stumps me
    can someone show me how this is done? the answer is to be in the form 2^n
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  2. #2
    Member Awsom Guy's Avatar
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    ok not too hard. the answer is 2^1. When your adding indices you add the top and when your subtracting them you subtract the indices. Try check this website out:
    Subtracting Indices (with worked solutions & videos)
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  3. #3
    Senior Member furor celtica's Avatar
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    thanks for trying to help kid but you are really wrong. i think you should review your lessons and check out the reliability of your websites, i think anybody could see this right away.
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  4. #4
    Super Member Quacky's Avatar
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     (2^{100}) - (2^{99})
    I'd take out a common factor of 2^{99}
    =2^{99}(2-1)
     =2^{99}(1)

    This will need verification.

    Actually, I am sure that I am correct.

    2\times2^{99}=2^{100}
    Substituting this into the first equation:
     2^{100} - 2^{99}
    2(2^{99})-2^{99}
    =1(2^{99})
    =2^{99}
    Last edited by Quacky; February 10th 2010 at 07:45 AM.
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  5. #5
    Super Member Quacky's Avatar
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    I had to make quite a few edits due to my rushed answer. The correct answer is displayed above.
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