# indice thing 1

• February 10th 2010, 01:08 AM
furor celtica
indice thing 1
(2^100) - (2^99)
im supposed to be doing pretty advance stuff but this just stumps me
can someone show me how this is done? the answer is to be in the form 2^n
• February 10th 2010, 01:47 AM
Awsom Guy
ok not too hard. the answer is 2^1. When your adding indices you add the top and when your subtracting them you subtract the indices. Try check this website out:
Subtracting Indices (with worked solutions & videos)
• February 10th 2010, 03:11 AM
furor celtica
thanks for trying to help kid but you are really wrong.(Crying) i think you should review your lessons and check out the reliability of your websites, i think anybody could see this right away.
• February 10th 2010, 07:21 AM
Quacky
$(2^{100}) - (2^{99})$
I'd take out a common factor of $2^{99}$
$=2^{99}(2-1)$
$=2^{99}(1)$

This will need verification.

Actually, I am sure that I am correct.

$2\times2^{99}=2^{100}$
Substituting this into the first equation:
$2^{100} - 2^{99}$
$2(2^{99})-2^{99}$
$=1(2^{99})$
$=2^{99}$
• February 10th 2010, 07:25 AM
Quacky
I had to make quite a few edits due to my rushed answer. The correct answer is displayed above.