What have you tried.
Name the prices.
A, B, C, and D perhaps.
B+C+D = 42
A+C+D = 40
Let's see what you get.
Hey guys, I am a new poster around here and I really can use a hand here!
I am in high school and I just cant do this one problem even though I have tried for hours...
So here's the deal, its a problem with 4 books and I need to find the prices for each one.
the clues are
- all the books without the 1st one gives a total of 42$
- all the books without the 2nd one gives a total of 40$
- all the books without the 3rd one gives a total of 38$
- all the books without the 4th one gives a total of 36$
Thank you for your time!
Any help or advices would be gladly appreciated!
Why did you introduce 'X'? Get rid of that. It's cute, but it doesn't get you anywhere.
Have you the ability to solve a well-defined 4x4 system of equations? The coefficients certainly are not challenging.
Just for the record, X = 52, but the problem statement certainly does not ask for that.