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Math Help - Radio-active decay problem.

  1. #1
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    Radio-active decay problem.

    I have the following equation.

    N/6= N*exp(-.0001216t)

    Then I want to solve to t, and the solution is ln(6)/.00001216

    I must be missing something....why is ln(6) and not ln(1/6)?
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  2. #2
    Senior Member
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    Quote Originally Posted by tactical View Post
    I have the following equation.

    N/6= N*exp(-.0001216t)

    Then I want to solve to t, and the solution is ln(6)/.00001216

    I must be missing something....why is ln(6) and not ln(1/6)?
    N/6= N*exp(-.0001216t)

    1/6= exp(-.0001216t)

    6= exp(0.0001216t)

    \ln 6= (0.0001216t)

    t = \frac{\ln 6}{0.0001216}
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  3. #3
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    Quote Originally Posted by tactical View Post
    I have the following equation.

    N/6= N*exp(-.0001216t)

    Then I want to solve to t, and the solution is ln(6)/.00001216

    I must be missing something....why is ln(6) and not ln(1/6)?
    You could also write the answer as t= ln(1/6)/(-.0001216). Now ln(1/6)= -ln(6).
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