Hello, I have a question regarding a problem..
Problem states
24k^3m-375m^4 = ?
is there a special factorization method to solve this problem? is this a prime polynomial?
From what I can see there is a factor of $\displaystyle 3m$ so lets start there:
$\displaystyle 3m(8k^3-125m^3)$
The expression in the brackets is the difference of two cubes( $\displaystyle 8 = 2^3$ and $\displaystyle 125 = 5^3$). The formula for the difference of two cubes is $\displaystyle a^3-b^3 = (a-b)(a^2+ab+b^2)$
$\displaystyle 3m(2k-5m)(4k^2+10mk+25m^2)$
As far as I know it will not factor further
thanks, i got it..... if you dont mind i have another question regarding a question with simplifying operations it states
x/(x-1)^2 - 2/x(x-1), the books says that I have to get a common denominator and then subtract the numerator from each other... How exactly do I get a common denomination for this?
thanks