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Math Help - Factoring

  1. #1
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    Factoring

    Hello, I have a question regarding a problem..

    Problem states

    24k^3m-375m^4 = ?

    is there a special factorization method to solve this problem? is this a prime polynomial?
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by cokeclassic View Post
    Hello, I have a question regarding a problem..

    Problem states

    24k^3m-375m^4 = ?

    is there a special factorization method to solve this problem? is this a prime polynomial?
    From what I can see there is a factor of 3m so lets start there:

    3m(8k^3-125m^3)

    The expression in the brackets is the difference of two cubes( 8 = 2^3 and 125 = 5^3). The formula for the difference of two cubes is a^3-b^3 = (a-b)(a^2+ab+b^2)

    3m(2k-5m)(4k^2+10mk+25m^2)

    As far as I know it will not factor further
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  3. #3
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    thanks, i got it..... if you dont mind i have another question regarding a question with simplifying operations it states

    x/(x-1)^2 - 2/x(x-1), the books says that I have to get a common denominator and then subtract the numerator from each other... How exactly do I get a common denomination for this?


    thanks
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  4. #4
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    Quote Originally Posted by cokeclassic View Post
    thanks, i got it..... if you dont mind i have another question regarding a question with simplifying operations it states

    x/(x-1)^2 - 2/x(x-1), the books says that I have to get a common denominator and then subtract the numerator from each other... How exactly do I get a common denomination for this?


    thanks
    a common denominator contains all the factors of each individual denominator ...

    x(x-1)^2 is the common denominator.


    btw ... in future, start a new problem w/ a new thread.
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