Thread: Remainder Theorem

"Use the remainder theorem to find the remainder quickly when the polynomial on the left is divided by the linear binomial on the right"

1. x^5 - 3x^2 + 14 by (x+2)

2. x^51 + 51 by (x+1)


I have absolutely no clue how to either of these...Thanks

Originally Posted by Trentt

"Use the remainder theorem to find the remainder quickly when the polynomial on the left is divided by the linear binomial on the right"

1. x^5 - 3x^2 + 14 by (x+2)

2. x^51 + 51 by (x+1)


I have absolutely no clue how to either of these...Thanks

for the first one you substitue x=-2 because of some reason that i can't remember and for the second you substitue x=-1 for the same reason, it should give you the remainder.

I need you to be a bit more specifi; I have to show proper work on my test.

Originally Posted by jonannekeke

for the first one you substitue x=-2 because of some reason that i can't remember and for the second you substitue x=-1 for the same reason, it should give you the remainder.

that's nice! "i don't know why, i just know"

it's alright though. you're the man jonannekeke

Originally Posted by Jhevon

that's nice! "i don't know why, i just know"

With that type of atitude I can solve the Birch-Swinnerton Dyer conjecture.

Originally Posted by Trentt

I need you to be a bit more specifi; I have to show proper work on my test.

see this, if you still don't get it, get back to me Remainder Theorem

In my text book it says:

If a polynomial f(x) is divided by (ax - b) then the remainder is f(b/a)

in your case:
Compare (x + 2) which is the same as (1x + 2) to (ax - b), so a=1, b=-2 and the remainder is f(-2/1)

Does that help?