Remainder Theorem

"Use the remainder theorem to find the remainder quickly when the polynomial on the left is divided by the linear binomial on the right"

1. x^5 - 3x^2 + 14 by (x+2)

2. x^51 + 51 by (x+1)


I have absolutely no clue how to either of these...Thanks

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Originally Posted by Trentt

"Use the remainder theorem to find the remainder quickly when the polynomial on the left is divided by the linear binomial on the right"

1. x^5 - 3x^2 + 14 by (x+2)

2. x^51 + 51 by (x+1)


I have absolutely no clue how to either of these...Thanks

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for the first one you substitue x=-2 because of some reason that i can't remember and for the second you substitue x=-1 for the same reason, it should give you the remainder.

I need you to be a bit more specifi; I have to show proper work on my test.

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Originally Posted by jonannekeke

for the first one you substitue x=-2 because of some reason that i can't remember and for the second you substitue x=-1 for the same reason, it should give you the remainder.

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that's nice! "i don't know why, i just know"

it's alright though. you're the man jonannekeke :)

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Originally Posted by Jhevon

that's nice! "i don't know why, i just know"

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With that type of atitude I can solve the Birch-Swinnerton Dyer conjecture.

Quote:

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Originally Posted by Trentt

I need you to be a bit more specifi; I have to show proper work on my test.

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see this, if you still don't get it, get back to me Remainder Theorem

In my text book it says:

If a polynomial f(x) is divided by (ax - b) then the remainder is f(b/a)

in your case:
Compare (x + 2) which is the same as (1x + 2) to (ax - b), so a=1, b=-2 and the remainder is f(-2/1)

Does that help?