ok im having the hardest time getting an answer for this problem
A marketing firm estimates that n monthsafter the introduction of a clients new product, f(n) thousand household will use it, where
f(n) = 10/9n(12 - n), 0<=n<=12
<=, less than equal, or greater than equal
10/9 is a fraction.
b. How long will it take for household use to reach a maximum? c. How many households will use the product when it reaches its maximum? d. The client must have 3 thousand households using the product in order to break even. How many months will it take before 3 thousand households use the product? (Give the decimal value of n.)
i got answers for b and c, but i can't get d... ive tried the quadratic formula and im stumped
a.) was graph the equation which i got already
Thanks for anyhelp
February 8th 2010, 05:38 PM
Well, look at the equation you're given:
f(n) = (10/9)(12-n)
Think about what this function does. After 1 month, we can find how many households use the product:
f(n) = (10/9)(12 - 1) = 12.2 thousand households
Now, if we KNOW that 3 thousand households use the product, we simply work backwards to find how many months that's at. What part of the function does 3 thousand correspond to?
February 8th 2010, 06:19 PM
i think you miss quoted part of the equation, but thats fine.
you forgot the n after 10/9
heres what i come up with as far as working with 3000