Thread: Finding a polynomial function

"write a polynomisl function of least degree that has real coefficients, the givern zeros, and a leading coefficient of 1."

9. (2,-1,5)

I have tried using three- y=ax^2=bx+c to solve it... in vain

Originally Posted by integral

"write a polynomisl function of least degree that has real coefficients, the givern zeros, and a leading coefficient of 1."

9. (2,-1,5)

I have tried using three- y=ax^2=bx+c to solve it... in vain

Hi integral,

If 2, -1, and 5 are zeros, then (x - 2), (x + 1), and (x - 5) are factors of the polynomial.

Therefore f(x) = (x - 2)(x + 1)(x - 5).