"write a polynomisl function of least degree that has real coefficients, the givern zeros, and a leading coefficient of 1." 9. (2,-1,5) I have tried using three- y=ax^2=bx+c to solve it... in vain
Last edited by mr fantastic; February 8th 2010 at 02:06 AM. Reason: Changed post title
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Originally Posted by integral "write a polynomisl function of least degree that has real coefficients, the givern zeros, and a leading coefficient of 1." 9. (2,-1,5) I have tried using three- y=ax^2=bx+c to solve it... in vain Hi integral, If 2, -1, and 5 are zeros, then (x - 2), (x + 1), and (x - 5) are factors of the polynomial. Therefore f(x) = (x - 2)(x + 1)(x - 5).
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