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Math Help - Simplify

  1. #1
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    Simplify

    How would you simplify this?

    (a-b)^2(a+b)2
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  2. #2
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    Quote Originally Posted by l flipboi l View Post
    How would you simplify this?

    (a-b)^2(a+b)2
    (a-b)^2(a+b)^2 = (a-b)(a+b)(a-b)(a+b) = (a^2-b^2)(a^2-b^2) = (a^2-b^2)^2

    this is what you want?
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  3. #3
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    Quote Originally Posted by l flipboi l View Post
    How would you simplify this?

    (a-b)^2(a+b)2
    if you meant ...

    (a-b)^2(a+b)^2 ...


    (a-b)(a-b)(a+b)(a+b)<br />

    (a-b)(a+b)(a-b)(a+b)

    (a^2-b^2)(a^2-b^2)

    (a^2-b^2)^2

    btw, I do not consider this to be "simplification" ... just changing the expression's looks.
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  4. #4
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    Quote Originally Posted by l flipboi l View Post
    How would you simplify this?

    (a-b)^2(a+b)2
    You can't simplify the expression, you just can change the expression's look (as skeeter did in his post). You don't have a denominator that could be simplified with the expression (example).
    Last edited by felper; February 6th 2010 at 05:05 PM.
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  5. #5
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    Quote Originally Posted by felper View Post
    You can't simplify the expression, you just can change the expression's look. You don't have a denominator that could be simplified with the expression.
    I thought I said that ... ?

    anyway, lack of a denominator does not mean an expression cannot be simplified.
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  6. #6
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    Quote Originally Posted by skeeter View Post
    I thought I said that ... ?

    anyway, lack of a denominator does not mean an expression cannot be simplified.
    Oh sorry, i've quoted wrongly. I'll edit
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  7. #7
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    oops sorry, it should be (a-b)^2(a+b)^2....

    is it also possible to have it like this?

    and distribute out the terms.

    (a^2-2ab+b^2)(a^2+2ab+b^2)
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  8. #8
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    Quote Originally Posted by skeeter View Post
    if you meant ...

    (a-b)^2(a+b)^2 ...


    (a-b)(a-b)(a+b)(a+b)<br />

    (a-b)(a+b)(a-b)(a+b)

    (a^2-b^2)(a^2-b^2)

    (a^2-b^2)^2

    btw, I do not consider this to be "simplification" ... just changing the expression's looks.
    Just wondering, should it be (a-b)(a+b) = (a-b)^2?

    (a-b)(a+b)(a+b)(a+b)
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  9. #9
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    Quote Originally Posted by l flipboi l View Post
    Just wondering, should it be (a-b)(a+b) = (a-b)^2?
    No,..

    (a-b)(a+b) = a^2 - b^2 \not = (a-b)^2
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