i need help on this question that says rationalize the denominator and simplify.
this is the problem::
+ 1
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thank you
Multiply by it's conjugate where the conjugate is the same numbers with the opposite sign between them:
$\displaystyle \frac{\sqrt3 +1}{\sqrt{3}+\sqrt{2}}$
The conjugate is $\displaystyle \sqrt{3}\sqrt{2}$
$\displaystyle \frac{\sqrt3 +1}{\sqrt{3}+\sqrt{2}} \cdot \frac{\sqrt{3}\sqrt{2}}{\sqrt{3}\sqrt{2}} = \frac{(\sqrt{3} +1)(\sqrt{3}\sqrt{2})}{(\sqrt{3}+\sqrt{2})(\sqrt{3}\sqrt{2})}$
Use the difference of two squares on the denominator