(2^-x)sinx = 1/2x - 1
My teacher said to use logs, but I'm useless at them
I would really appreaciate any help given
Thanks in advance!
Having two different transcendental functions makes that a really difficult equation, particularly with that (1/2)x- 1. Unless you mean = 2^{-x}[/tex]. If so, it is still difficult but you might be able to write sin(x) as and write 2^{-x} as
Having two different transcendental functions makes that a really difficult equation, particularly with that (1/2)x- 1. Unless you mean = 2^{-x}[/tex]. If so, it is still difficult but you might be able to write sin(x) as and write 2^{-x} as
The mixture of exponential and linear functions of x still means this is likely to involve our old favourite, Lambert's W.