Thread: prove the identity

if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

[(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3
please help!!!

Originally Posted by earthboy

if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

[(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3
please help!!!

is that menth to be
or as it is written

Quote:
Originally Posted by earthboy
if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

[(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3
please help!!!

is that menth to be
or as it is written

i meant the first exp. not the second one

Originally Posted by earthboy

if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

[(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3

start by combining the first three terms on the left with the last term using the common denominator