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Math Help - prove the identity

  1. #1
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    Talking prove the identity

    if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

    [(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3
    please help!!!
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  2. #2
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    Quote Originally Posted by earthboy View Post
    if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

    [(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3
    please help!!!
    is that menth to be \frac{6abc}{(x-a)(x-b)(x-c)}
    or as it is written \frac{6abc}{x-a}\times(x-b)(x-c)
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  3. #3
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    Quote:
    Originally Posted by earthboy
    if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

    [(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3
    please help!!!


    is that menth to be
    or as it is written
    i meant the first exp. not the second one
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  4. #4
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    Quote Originally Posted by earthboy View Post
    if x = (2ab+2bc+2ca)/(a+b+c), then prove that,

    [(x+a)/(x-a)] + [(x+b)/(x-b)] +[(x+c)/(x-c)] - [6abc/(x-a)(x-b)(x-c)] = 3
    start by combining the first three terms on the left with the last term using the common denominator (x-a)(x-b)(x-c)
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