Your sequence is full of odd numbers therefore one is not the answer.
Let's try 2 numbers, I can see that 219 and 221 are in your sequence and add to the desired result. We are finished.
find the minimum number of terms that must be taken from the sequence 3, 5, 7, 9,...so the sum is at least 440.
we are given this formula to solve the question..
s=n/2 [2a+(n-1)d]
where,
s=sum of the first n term,
n=number of term,
a=first term,
d=common difference.
the question ask to find the value of n..
some one out there please help me..