Hi could somebody please help me. I really dont understand how to approach this question. the coefficient of x^2 is 3/8 in the expansion of (1+x/n)^n. find n. any sort of help would be much appreciated. thanks.
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Originally Posted by wahhdoe Hi could somebody please help me. I really dont understand how to approach this question. the coefficient of x^2 is 3/8 in the expansion of (1+x/n)^n. find n. The binomial expansion of is You can see from that what the coefficient of is (in terms of n). Put it equal to 3/8 and solve for n.
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