Hii ! Either $\displaystyle a,b,c > 0$ Find the Minimum of x : $\displaystyle x=\frac{a+3c}{a+2b+c}$ $\displaystyle + \frac{4b}{a+b+2c}$ $\displaystyle - \frac{8c}{a+b+3c}$
Last edited by Perelman; Feb 1st 2010 at 12:50 PM.
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