# Math Help - Intermediate Algebra - Factoring #2

1. ## Intermediate Algebra - Factoring #2

Hello, please look at the picture below.
I don't know where that 3 went... Please tell me?
Also the next problem that starts from 4(3-....
the three goes missing again. Could you tell me how it works??

Thank you!

2. $5(2- x)+ 2(2- x)^3$

To see exactly what is going on, replace those "(2- x)" terms by the single letter, a. That is $5a- 2a^3= (5)a- (2a^2)a$ and since there is an " $a^2$" in each term we can factor it out: $a^2(5- 2a)$.

Now put (2-x) back in place of each "a": $5(2- x)^2- 2(2- x)^3= (2-x)^2(5- (2- x))$

3. Thanks! I think I got the concept now. I need more practice though.