I am unable to come up with the answer to the key for this problem. Can someone give it a try?
(4x^2+x-6)/(x^2+3x+2)-3x/(x+1)+5/(x+2)
Thanks in advance!
I am unable to come up with the answer to the key for this problem. Can someone give it a try?
(4x^2+x-6)/(x^2+3x+2)-3x/(x+1)+5/(x+2)
Thanks in advance!
Dear sprivitor,
$\displaystyle \frac{4x^2+x-6}{(x+1)(x+2)}-\frac{3x}{x+1}+\frac{5}{x+2}$
$\displaystyle \frac{4x^2+x-6-3x(x+2)+5(x+1)}{(x+1)(x+2)}$
By simplification we would get,
$\displaystyle \frac{x^2-1}{(x+1)(x+2)}$
$\displaystyle \frac{(x+1)(x-1)}{(x+1)(x+2)}$
$\displaystyle \frac{x+1}{x+2}$
Hope this helps.
[quote=sprivitor;448278]I am unable to come up with the answer to the key for this problem. Can someone give it a try?
(4x^2+x-6)/(x^2+3x+2)-3x/(x+1)+5/(x+2)
[quote]
Did you realise that x^2+3x+2 = (x+1)(x+2) ?