I am unable to come up with the answer to the key for this problem. Can someone give it a try?

(4x^2+x-6)/(x^2+3x+2)-3x/(x+1)+5/(x+2)

Thanks in advance!

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- Jan 30th 2010, 05:29 PMsprivitorSimplify Equation
I am unable to come up with the answer to the key for this problem. Can someone give it a try?

(4x^2+x-6)/(x^2+3x+2)-3x/(x+1)+5/(x+2)

Thanks in advance! - Jan 30th 2010, 05:49 PMSudharaka
Dear sprivitor,

$\displaystyle \frac{4x^2+x-6}{(x+1)(x+2)}-\frac{3x}{x+1}+\frac{5}{x+2}$

$\displaystyle \frac{4x^2+x-6-3x(x+2)+5(x+1)}{(x+1)(x+2)}$

By simplification we would get,

$\displaystyle \frac{x^2-1}{(x+1)(x+2)}$

$\displaystyle \frac{(x+1)(x-1)}{(x+1)(x+2)}$

$\displaystyle \frac{x+1}{x+2}$

Hope this helps. - Jan 30th 2010, 05:53 PMWilmer
[quote=sprivitor;448278]I am unable to come up with the answer to the key for this problem. Can someone give it a try?

(4x^2+x-6)/(x^2+3x+2)-3x/(x+1)+5/(x+2)

[quote]

Did you realise that x^2+3x+2 = (x+1)(x+2) ? - Jan 30th 2010, 06:09 PMsprivitor
Thank you. I now see my problem was with a simple negative sign.

-3X/(X+1) + 5 / (X+2)

I made the WRONG assumption that this equals

-[3X/(X+1)**+**5 / (X+2)]

it is equal to

-[3X/(X+1)**-**5 / (X+2)]