1. ## Factor (Simple Question)

Hello,

How would you factor this to solve for x?

$(x^2-x^4)=0$

2. You can first take out the common factor of $x^2$

THen you have:

$x^2(1-x^2)=0$

$x^2(1+x)(1-x)=0$

So $x=0$ or $x=\pm 1$