Hello, How would you factor this to solve for x? $\displaystyle (x^2-x^4)=0$
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You can first take out the common factor of $\displaystyle x^2$ THen you have: $\displaystyle x^2(1-x^2)=0$ $\displaystyle x^2(1+x)(1-x)=0$ So $\displaystyle x=0$ or $\displaystyle x=\pm 1$
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