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Math Help - Application of Linear Law to Non-linear Relations

  1. #1
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    Application of Linear Law to Non-linear Relations

    Given x and y are related by the equation xy=px+q/x where p and q are constant.A straight line graph is obtained by plotting y against 1/(x^2),it passes through the points (0,0.5) and (4,-2.5).calculate the value of p and q.

    please help..
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  2. #2
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    hi

    xy = px +q/x /divide by x

    then y = p + q/(x^2) rearange terms

    y = q/x^2 +p

    we know that when x = 0 then y = 0.5

    0.5 = (q/o^2) +p that gives p = 0.5

    Likewise plug in the values from (4,-2.5)

    y = q/x^2 + 0.5 and there it is.

    you get -2.5 = q/4 +0.5 and solve for q
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