Given x and y are related by the equation xy=px+q/x where p and q are constant.A straight line graph is obtained by plotting y against 1/(x^2),it passes through the points (0,0.5) and (4,-2.5).calculate the value of p and q.
please help..
Given x and y are related by the equation xy=px+q/x where p and q are constant.A straight line graph is obtained by plotting y against 1/(x^2),it passes through the points (0,0.5) and (4,-2.5).calculate the value of p and q.
please help..
$\displaystyle xy = px +q/x$ /divide by x
then $\displaystyle y = p + q/(x^2)$ rearange terms
$\displaystyle y = q/x^2 +p$
we know that when x = 0 then y = 0.5
$\displaystyle 0.5 = (q/o^2) +p$ that gives $\displaystyle p = 0.5$
Likewise plug in the values from (4,-2.5)
$\displaystyle y = q/x^2 + 0.5$ and there it is.
you get $\displaystyle -2.5 = q/4 +0.5$ and solve for q