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Thread: straight line

  1. January 29th 2010, 02:24 AM #1
    mastermin346
    mastermin346 is offline
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    straight line

    Explain how a straight line graph can be drawn from the equation 16p^2(x)=(y-q)^2 where p and q are constants.State the gradient and the y-intercept of the straight line graph in terms of p and q.
    Last edited by mastermin346; January 29th 2010 at 03:07 AM.
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  2. January 29th 2010, 04:15 AM #2
    Henryt999
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    Tricky

    16x*p^2 = (y-q)^2

    Take the square root of both sides:

    4p \sqrt{x} = y-q

    or

    y = 4p \sqrt{x} +q
    Last edited by mr fantastic; January 29th 2010 at 12:29 PM. Reason: Fixed latex.
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