How many gallons of 40 percent alcohol solution must be mixed with 70 percent solution to obtain 30 gallons of a 52 percent alcohol solution?
posted by apple 2009
1 set up an equation in x as thelean fraction and 30-x the rich fraction. The sum of the alc in each fraction in terms of x = 30 times .52
2 use the lever principle
52-40= 12 the rich fraction
70-52= 18 the lean fraction
This is your answer . Your equation must get the same result