# Math Help - questions on radicals

1. ## questions on radicals

how do you simplify this ${\sqrt[5]{-32}}$?

2. Originally Posted by Anemori
how do you simplify this ${\sqrt[5]{-32}}$?
$\sqrt[5]{-32}=( - (2)^5 )^{ \frac{1}{5} } = -2$

3. Originally Posted by Anemori
how do you simplify this ${\sqrt[5]{-32}}$?
does it help to know that $2^5 = 32$ ?

4. You're looking for what number raised to the fifth power equals 32.

2x2x2x2x2=32

Since you have an odd numbered root (5th root) the negative sign is ok.

${\sqrt[5]{-32}}=-2$

I'm not sure if there's something else you're looking for but -2 is as simple as it gets.

5. Originally Posted by Anemori
how do you simplify this ${\sqrt[5]{-32}}$?
Because x^5, where the exponent is odd (odd number of integers multiplied by 1 negative integer is always negative), you can treat
${\sqrt[5]{-32}}$ as:

(-)(32^(1/5))