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Math Help - questions on radicals

  1. #1
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    questions on radicals

    how do you simplify this  {\sqrt[5]{-32}} ?
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  2. #2
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    Quote Originally Posted by Anemori View Post
    how do you simplify this  {\sqrt[5]{-32}} ?
    \sqrt[5]{-32}=( - (2)^5 )^{ \frac{1}{5} } = -2
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  3. #3
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    Quote Originally Posted by Anemori View Post
    how do you simplify this  {\sqrt[5]{-32}} ?
    does it help to know that 2^5 = 32 ?
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  4. #4
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    You're looking for what number raised to the fifth power equals 32.

    2x2x2x2x2=32

    Since you have an odd numbered root (5th root) the negative sign is ok.


    {\sqrt[5]{-32}}=-2

    I'm not sure if there's something else you're looking for but -2 is as simple as it gets.
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  5. #5
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    Quote Originally Posted by Anemori View Post
    how do you simplify this  {\sqrt[5]{-32}} ?
    Because x^5, where the exponent is odd (odd number of integers multiplied by 1 negative integer is always negative), you can treat
     {\sqrt[5]{-32}} as:

    (-)(32^(1/5))
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