I love these kinds of problems:

First you must understand that this problem requires tail over head.

32=tail

1=head

First the factors of 32 the tail

1,2,4,8,16,32 over the factors of the head which is one

1

Now you must put all of your factors together you solution can be + or -

here we go:

1

2

4

8

16

32

-1

-2

-4

-8

-16

-32

Which ones are the zeros?

2

This is yourONLYsolution.

I will let someone else show you how to use synthetic division because latex is down and it would be impossible for you understand where I am coming from.