Thread: simplify..need help

Hello ,
I need some king person to show me how to finish off my question,

in the picture attached the correct answer is in green in the bottom corner, I cant seem to get it?
Please

Did you apply the distributive law when you multiplied the first equation.

4*(1-x^2)^(1/2) + 2*x(1-x^2)^(-1/2)*(-2*x)

Then, your common denominator was correct. But you would end up with this,

numerator: (4*(1-x^2) - 4*x^2)

denominator: ((1-x^2)^(1/2))

I don't know how to do all the code, but if you apply the distributive law you should end up with what is in green; if unclear let me know.

Hello
I am not sure how to do the distributive law?
Can you tell/show please?
Thanks

The distributive law is like this.

say we have x(y + z)

then, x(y+z) = xy + xz and if it were like this (y + z)x = yx + zx.

So, an example would be like this....say we have the following:

2(x-4) = 2x - 8. What you are doing is you are taking the 2 and multiplying each of the elements in parentheses by it.

Another example:
3(y + 8) = 3y + 24
5(z - 3) = ? (Think about this one)

Originally Posted by mesmo

Did you apply the distributive law when you multiplied the first equation.

4*(1-x^2)^(1/2) + 2*x(1-x^2)^(-1/2)*(-2*x)

Then, your common denominator was correct. But you would end up with this,

numerator: (4*(1-x^2) - 4*x^2)

denominator: ((1-x^2)^(1/2))

I don't know how to do all the code, but if you apply the distributive law you should end up with what is in green; if unclear let me know.

Hello, 5(z - 3) =5z -15
Yes I understand the law,I didnt know what you meant

The part I am mixed up with is (4*(1-x^2) - 4*x^2)
How do I still have 1-x^2 in the numerator? Did I not put it in the denominator?

Originally Posted by wolfhound

Hello, 5(z - 3) =5z -15
Yes I understand the law,I didnt know what you meant

The part I am mixed up with is (4*(1-x^2) - 4*x^2)
How do I still have 1-x^2 in the numerator? Did I not put it in the denominator?

You did put it in the denominator. But remember what you put in the denominator

(1-x^2)^(1/2)...

.Once that is in the denominator, in order to create like denominators for everything you have to multiply the other term by (1-x^2)^1/2 and when you multiply it by the other one, you'll end up with (1-x^2)....

remember (1/2) + 5...in order to add these, we need like denominators so we multiply the 5 by 2 and put that over 2. which will yield (1/2) + (10/2)....